750 joule of work is required to to transfer 10c of charge between two points resistance of 25 ohm then calculate the electric current
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Answer:
w=750 J
Q= 10C
R=26 ohm
W=V/Q
750= V/10
7500=V
V=7500
V=IR
7500=I ×25
7500/25= I
1500/5 =I
300=I
I=300 WATT
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