75°C to 35°C the amount of crystals deposited out are much less.
ii) When 800 ml. of a saturated solution of salt 'X' is cooled from 75°C to 35°C a
ing, but when 800 ml. of a saturated solution of salt 'Y' is cooled again from
Answers
Explanation:
Explanation:weight of salt = 90 gram,
Explanation:weight of salt = 90 gram, solubility = 50
Explanation:weight of salt = 90 gram, solubility = 50sing formula
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute =
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolution
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50=
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50= weightofsolventinsaturatedsolutio
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50= weightofsolventinsaturatedsolutio90gm
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50= weightofsolventinsaturatedsolutio90gm
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50= weightofsolventinsaturatedsolutio90gm ×100
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50= weightofsolventinsaturatedsolutio90gm ×100so weight of solvent in saturated solution =
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50= weightofsolventinsaturatedsolutio90gm ×100so weight of solvent in saturated solution = 50
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50= weightofsolventinsaturatedsolutio90gm ×100so weight of solvent in saturated solution = 5090gm
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50= weightofsolventinsaturatedsolutio90gm ×100so weight of solvent in saturated solution = 5090gm
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50= weightofsolventinsaturatedsolutio90gm ×100so weight of solvent in saturated solution = 5090gm ×100=180gm
Explanation:weight of salt = 90 gram, solubility = 50sing formula solubility of solute = weightofsolventinsaturatedsolutionweightofsoluteinsaturatedsolution ×100or 50= weightofsolventinsaturatedsolutio90gm ×100so weight of solvent in saturated solution = 5090gm ×100=180gmHence 180 gm of water is required to prepare a saturated solution.