75g benzine and 2.5 ethanoic acid (ch3 cooh) molarity find?
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The molar mass of ethanoic acid is
=> 2(12)+2(16)+4(1)
=> 60 g/mol.
Number of moles of ethanoic acid
=>2.5g ÷ 60g/mol
=> 0.04167 mol
The mass of benzene is 75 grams
=> 0.075 kg
The molality of ethanoic acid in benzene is the ratio of the number of moles of ethanoic acid to the mass of benzene (in kg).
=> 0.04167mol ÷ 0.075kg
=> 0.556m
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Answer:
0.556
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