Question

75g benzine and 2.5 ethanoic acid (ch3 cooh) molarity find?​

Answer 1

The molar mass of ethanoic acid is

=> 2(12)+2(16)+4(1)

=> 60 g/mol.

Number of moles of ethanoic acid

=>2.5g ÷ 60g/mol

=> 0.04167 mol

The mass of benzene is 75 grams

=> 0.075 kg

The molality of ethanoic acid in benzene is the ratio of the number of moles of ethanoic acid to the mass of benzene (in kg).

=> 0.04167mol ÷ 0.075kg

=> 0.556m

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OM!

Answer 2

Answer:

0.556

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