75g of ethylene glycol is dissolved in 500g water. The solution is placed in a refrigerator maintained at a temperature of 263.7K. What amount of ice will separate out at this temperature.
(Kf water = 1.86 K/m
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Answer:
258g
Explanation:
Depression in freezing point,
ΔTf = ΔTf ⁰ ( freezing point of pure solvent ) - Tf ( freezing point when non-volatile solute is dissolved in it)
= 273 - 263.7 K= 9.3 K
Weight of the solvent ( water) W = (Kf * w * 1000) / m * ΔTf
Where,
m -- molar mass of the solute ( ethylene glycol )
w -- weight of the solute.
Kf ( given ) = 1.86 K/m
W = ( 1.86 * 75 *1000 ) / 62 * 9.3
= 242g
Therefore, the amount of ice that would be separated from 500g of water at this temperature would be 500 - 242 = 258 Grams.
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