Question

75kg man stands on a lift 'what force does the floor exert on the man when the lift starts moving upward with an accerleration 2m/s^2

Answer 1

Normal force =MA+MG
=(75×2)+(75×9.8)
=150+735
=885N
Force exerted by floor on man will be equal to 885 Newton

Answer 2

Answer:

Force, F = 885 N

Explanation:

It is given that,

Mass of the man, m = 75 kg

Acceleration of the lift that is moving upward, $a=2\ m/s^2$

As the lift starts moving upward. Then the force the floor exert on the man is :

$F=mg+ma$

$F=m(g+a)$

$F=75\times (9.8+2)$

F = 885 N

So, the force the floor exert on the man is 885 N. Hence, this is the required solution.