Question

76. 'A' is twice as old as 'B'. Three year ago 'A
was three times as old as 'B' How old is 'A
now?
(A) 6 years
(B) 12 years
(C) 14 years
(D) 16 years​

Answer 1

Answer:

a questio is the right answer

Answer 2

Consider B’s present age as x years. So age of A is 2x years. 3 years ago, B’s age was (x-3) years, and A’s age was (2x-3)years. The equation for the age relation 3 years ago is,

3 B’s age = A’s age.

So, 3(x-3)= 2x -3.

3x-9 = 2x - 3.

x = 6.

So, B’s age is 6 years. And as A is twice as old as B at present. Therefore, A’s present age is 12 years