Math, asked by ronakthukral55, 3 months ago

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6. Find the surface area of a box whose length is 40 cm, breadth 27 cm and height 10 cm.

Answers

Answered by surajghogare745
0

Answer:

The surface area of a box is 3520cm^2.3520cm

2

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Step-by-step explanation:

Given,

Length(l) = 40cm, breadth(b) = 27cm and height(h) = 10cm

To find, the surface area of a box = ?

We know that,

The surface area of a box = 2(lb+bh+hl)=2(lb+bh+hl)

= 2(40\times 27 + 27 \times 10 + 10 \times 40 )=2(40×27+27×10+10×40)

= 2(1080+270+400) cm^{2}=2(1080+270+400)cm

2

= 2\times 1750 cm^{2}=2×1750cm

2

= 3520cm^2=3520cm

2

Hence, the surface area of a box is 3520cm^2.3520cm

2

.

Answered by Anonymous
1

Answer:

u calculate it urself

Step-by-step explanation:

try to imagine that cuboidal and then calculate surface area of each surface u get and finally add them up

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