Question

76. Three blocks of masses m,,m, and m, are
connected by massless strings as shown in the figure
on a frictionless table. Forces of 10 N and 40 Nare
applied on them as shown in diagram. If m, = 10kg,
m, = 6 kg and m, = 4 kg, then tension T, will be:-
T
T2
10 Nm
m,
mi
40 N
(1) 10 N (2) 20 N (3) 25 N
(4) 35 N​

Answer 1

Answer:

4) 35N

Step-by-step explanation:

Total mass of system=20kg

Acceleration of system=A

∴A=m/F

=20/40

=2

Because string t2 pulls 1 an 2 blocks

therefore

 t2=( m1+m2)a

=(10+6)×2

=32N

Hence,

option (D) is correct answer.