Math, asked by StarTbia, 1 year ago

768 - By which smallest number this number should be multiplied, so that the result becomes a perfect square? Find the square root of the result obtained.

Answers

Answered by CaptainBrainly
13
Hey Mate !!

The prime Factorization of 768 is,

768 = 2 × 2 × 2 ×2 × 2 × 2 × 2 × 2 × 3

Here, We can see the number 2 is paired 4 times while 3 is remained unpaired.

When we multiply 768 with 3. The product is 768 × 3 = 2304

The prime Factorization of 2304 is

2304 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3

All numbers are paired. Hence, 2304 is a perfect square. The Square root is :

= 2 × 2 × 2 × 2 × 3

= 48

Therefore,

The Square root of 2304 is 48
Answered by mysticd
5

Solution :


Resolving 768 into prime factors,


we get


768 = 2×2×2×2×2×2×2×2×3


=(2×2)(2×2)(2×2)(2×2)×3


We can see that 2,2,2 and 2


exists in pairs.


3 is alone .


So,we should multiply the


given number by 3 to get a


perfect square .


Therefore,


the perfect square obtained is


768 × 3 = 2304 = ( 48 )²


Square root = √2304 = 48


••••

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