768 - By which smallest number this number should be multiplied, so that the result becomes a perfect square? Find the square root of the result obtained.
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Answered by
13
Hey Mate !!
The prime Factorization of 768 is,
768 = 2 × 2 × 2 ×2 × 2 × 2 × 2 × 2 × 3
Here, We can see the number 2 is paired 4 times while 3 is remained unpaired.
When we multiply 768 with 3. The product is 768 × 3 = 2304
The prime Factorization of 2304 is
2304 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3
All numbers are paired. Hence, 2304 is a perfect square. The Square root is :
= 2 × 2 × 2 × 2 × 3
= 48
Therefore,
The Square root of 2304 is 48
The prime Factorization of 768 is,
768 = 2 × 2 × 2 ×2 × 2 × 2 × 2 × 2 × 3
Here, We can see the number 2 is paired 4 times while 3 is remained unpaired.
When we multiply 768 with 3. The product is 768 × 3 = 2304
The prime Factorization of 2304 is
2304 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3
All numbers are paired. Hence, 2304 is a perfect square. The Square root is :
= 2 × 2 × 2 × 2 × 3
= 48
Therefore,
The Square root of 2304 is 48
Answered by
5
Solution :
Resolving 768 into prime factors,
we get
768 = 2×2×2×2×2×2×2×2×3
=(2×2)(2×2)(2×2)(2×2)×3
We can see that 2,2,2 and 2
exists in pairs.
3 is alone .
So,we should multiply the
given number by 3 to get a
perfect square .
Therefore,
the perfect square obtained is
768 × 3 = 2304 = ( 48 )²
Square root = √2304 = 48
••••
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