Math, asked by robinsonterang6897, 11 months ago

76n- 66n, where n is an integer >0, is divisible by
A.13
B.127
C.559
D.All of these

Answers

Answered by Anonymous
5
all of these because
For n = 1,
76n-66n = 76 -66
= (73)2-(63)2
= (73-63)( 73+63)
= (343-216)*(343+216)
= 127*559.
= 127 * 13 *43.
Clearly, it is divisible by 127, 13 as well as 559.
I hope this will help you
Similar questions