Question

77.5 gram of a gas occupies 5.6 litres of volume at STP the gas is

Answer 1

Molar gas volume at stp is :

1 mol = 22.4 litres

Moles of the gas is :

5.6/22.4 = 0.25 moles

Moles = mass / molar mass

Molar mass = mass / moles

77.5 / 0.25 = 310 g/mol

The gas with this molecular mass is :

(CO₂)₆NO₂

This is equivalent to C₆NO₁₄