Math, asked by thangamsrkn, 1 year ago

77!*(77!-2 * 54!)3/(77! + 54!)3 + 54! * (2 * 77! -54! )3 / (77!+ 54!)3=?

(a) 2*77!+2*54! (b) 77!-54! (c) 77!+54! (d) 2*77!-2* 54!

Answers

Answered by kvnmurty
14
answer is  (b)  77! - 54!

77!  *  (77!  - 2 * 54!)³ / (77! + 54!)³   +  54! * (2 * 77!  -  54!)³  / (77! + 54!)³

\frac{77! (77! - 2* 54!)^3 + 54!  (2* 77! - 54!)^3}{(77! + 54!)^3}\\\\Nr=77!^4-3*77!^3*2*54!+3*77!^2*2^2*54!^2-77!*2^3*54!^3\\\\+54!*2^3*77!^3-3*2^2*77!^2*54!^2+3*2*77!*54!^3-54!^4\\\\=77!^4-54^4+2*54!*77!*[77!^2-54!^2]\\\\=[77!^2-54!^2][77!+54!]^2\\\\LHS=Nr/Dr=\frac{[77!^2-54!^2]}{[77!+54!]}=77! - 54!


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