Question

77 sq.m. tripal is required to make a right circular conical tent. If the slant height of the tent is 7 m., then let us write by calculating, the base area of tent.​

Answer 1

✬ Area = 38.5 m² ✬

Step-by-step explanation:

Given:

• 77 m² tripal is required for making right circular tent.
• Slant height of tent is 7 m.

To Find:

• What is the base area of tent ?

Solution: Let measure of radius of base of tent be r m. Also ,circular tent is in the form of cone. Therefore,

➫ Tripal required to make tent = CSA of cone

As we know that

★ CSA of Cone = πrl ★

• Taking π = 22/7
• L = 7 m

$\implies{\rm }$ 77 = πrl

$\implies{\rm }$ 77 = 22/7(r)(7)

$\implies{\rm }$ 77 = 22r

$\implies{\rm }$ 77/22 = r

$\implies{\rm }$ 3.5 = r

So Radius of base of tent is 3.5 m

★ Base area of tent = πr² ★

$\implies{\rm }$ 22/7(3.5)²

$\implies{\rm }$ 22/7 (12.25)

$\implies{\rm }$ 269.5/7

$\implies{\rm }$ 38.5 m²

Hence, base area of tent is 38.5 m².

Answer 2

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Given :-

• Area of tripal = 77 m²

• Slant height of cone = 7 m

To Find :-

• Radius of the cone

• Base area of the cone

Solution :-

★ CSA of Cone = πrl

→ 22/7 × r × 7 = 77

→ 22r = 77

→ r = 77/22

→ r = 3.5 m

Radius of cone is 3.5 m

★ Base area of tent = πr²

→ Area = 22/7 × 3.5 × 3.5

→ Area = 22/7 × 12.25

→ Area = 269.5 / 7

→ Area = 38.5 m²

base area of tent is 38.5 m²