Question

77. The given figure shows
two isosceles triangles
ABC and DBC with
common base BC. AD
is extended to intersect
BC at point P. Show
that :
(i) AABD = AACD.
(ii) AABP = AACP.
(iii) AP bisects ZBDC.
(iv) AP is perpendicular bisector of BC.

Answer 1

Hey dude u haven't given the figure

Please attach the figure so that we can help u ❤️