78 For one mole of a van der Waals' gas when b=0 and
T= 300 K, the pV vs 1/V plot is shown below. The
value of the van der Waals constant a (atm L mol-?) is
24.64
23.1
pV(L atm mol)
21.6-
F
20.14.
0
2.0 3.0
1/V (mol L-1)
Answers
Answered by
2
Van der Waal's equation is (P+
V
2
a
)(V−b)=RT
As given that b=0
PV+
V
a
=RT⇒PV=RT−
V
a
Comparing with y=mx+c, Intercept (c)=RT, Slope (m)=−a
Slope=
x
2
−x
1
y
2
−y
1
=
3−2
20.1−21.6
=−1.5.
Thus, a=1.5.
Therefore, the correct option is C.
Answered by
2
Answer:
but, answer is complete circuit bro
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