Question

78. Maximum number of spectral lines obtained when
electrons in H-atom sample de-excite from fourth
excited state to ground state is
(1) 15
(2) 10
(3) 8
44) 6​

Answer 1

Answer:

Answer is 10,since by formula it is

(n exc - n ground)×(n exc - n ground - 1)/2

fourth excited state is n=5

so,(5-0)(5-0-1)/2=10

Answer 2

Answer:

The correct answer to this question is 15lines.

Explanation:

Given - Maximum number of spectral lines obtained when electrons in the H-atom sample de-excite from a fourth excited state to the ground state.

To Find - Choose the correct option.

Maximum number of spectral lines obtained when electrons in the H-atom sample de-excite from a fourth excited state to the ground state is 15

When an excited electron of an H atom emits the most emission lines in n = 6 drops to the ground state is $\frac{(n_{2} - n_{1}(n_{2} - n_{1} +1) }{2}$

= 5 × 6 / 2  

= 15lines

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