Physics, asked by bberztis0844, 7 months ago

78 mL of 2.5 M phosphoric acid is neutralized with 500 mL potassium hydroxide. What is the concentration of the base? Include the balanced chemical equation for the reaction

Answers

Answered by nirman95
2

Given:

78 mL of 2.5 M phosphoric acid is neutralized with 500 mL potassium hydroxide.

To find:

Concentration of the base.

Calculation:

Since the acid got completely neutralised by the base, we can say that:

n refers to "n - factor" ; S refers to strength of acid/base ; V refers to volume:

 \sf{(n1) \times (S1) \times (V1) = (n2) \times (S2) \times (V2)}

 \sf{ =  > 3 \times 2.5 \times 78= 1 \times  (S2)\times 500}

 \sf{ =  >  500 (S2) = 585}

 \sf{ =  > (S2) = \dfrac{ 585}{500}}

 \sf{ =  > (S2) = 1.17 \: M}

Hence, concentration of base is 1.17 M.

\boxed{\rm{\large{H_{3}PO_{4} + 3KOH \rightarrow K_{3}PO_{4} + 3H_{2}O}}}

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