78 ml sample of a gas is heated from 35 degree celsius to 80 degree Celsius at constant temperature. what is the final volume?
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0.089 L ≅ 89 ml
Explanation:
Given: V₁ = 78ml = 0.078 L V₂ = ?
T₁ = 35 + 273 = 308 K, T₂ = 80 + 273 = 353 K
we know that,
V₁/T₁ = V₂/T₂
V₂ = T₂V₁/T₁
= 353 × 0.078/ 308
= 0.089 L ≅ 89 ml
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