78. What is the normality of
0.3 M H3PO4, when it undergoes
the reaction as :
H3PO4 + 2OH- → HPO3- +2H20
(a) 0.3 N
(b) 0.15 N
(c) 0.6 N
(d) 0.9 N
Answers
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H3PO4 + 2OH ^- → HPO3^-2 +2H20
Normality =nfactor×molarity
N factor=Number of H+ ions replaced.
Here n factor is 2 ,since 2 H+ ions are replaced.
Normality =2×0.3=0.6N
Hence option C is coorrect
hope its help u !
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