Math, asked by kimgkhan, 1 year ago

780 rupees paid for a task which a can do in 6 days B in 8 days and can in 4 days. if all work together how much money should each receive?

Answers

Answered by snagasai1971gmailcom
5
A's one day work = 1/6
B's one day work = 1/8
C's one day work = 1/4
Now, if A,B and C work together, then
one day work = (1/6)+(1/8)+(1/4)
= 13/24
Therefore, no. of days needed to complete the work = 24/13 days
=1.8 days ( approximately )

Now,
money paid for doing task in 6,8 or 4 (i.e. 24 ) days = 780/-
Now it is obvious that if the work is done in less time than more money would be paid, i.e. lesser the time is taken to complete the task, more the money given.

Therefore,
Money paid to do work in 1.8 days = 780 + 24/1.8
= 780+ 13.3
=793.33/-

kimgkhan: what the amount each recive
Answered by mcneasam000
1


1
-1+1=1-7=1.
36832424

A's wages : B's wages : C's wages =1:1:1= 4 : 3 : 1.6824

C's share (for 3 days) = Rs.3 x1x 3200= Rs. 400

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