Question

7a^2+7b^2/7a^2-7b^2=113/13​

Answer 1

Answer:

7a²+7b²/7a²-7b² = 113/13

13(7a²+7b²) = 113(7a²-7b²)

91a²+91b² = 791a²-791b²

91a²-791a² = -791b²-91b²

-700a² = -882b²

700a² = 882b²

882b²-700a² =0

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Answer 2

$\huge\bf\underbrace{ANSWER}$

$7a²+7b²/7a²-7b²=113/13$

$⇒7a²+7b²/7a²-7b²=113/13$

applying componendo and divinendo

$⇒(7a²+7b²)+(7a²-7b²)/(7a²+7b²)-(7a²-7b²)=113+13/113-13$

$⇒∴14a²/4b²=126/100$

$⇒7a²/2b²=63/50$

$⇒]a²/b²=9/25$

$⇒∴a/b=√9/25$

$⇒3/5$

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