Math, asked by nidhishukla40, 5 months ago

(7a +21) (19z +57) ÷19(a+3)

Answers

Answered by angshu12

2

Answer:

(7a +21) (19z +57) ÷19(a+3)

= 7(a+3) 19 (z +3) × 19

(a+3)

= 7×19×19(z+57)

= 2527( z+57)

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