(7a+3)(2a+5)(3a-4).this the the question of which i want the answer pls help!
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Answer:
-14a^3-41a^2-15a
Step-by-step explanation:
(7a+3)(2a+5)(3a-4)
={7a(2a+5)+3(2a+5)}(3a-4)
=(14a^2+35a+6a+15)(3a-4)
=3a(14a^2+41a+15)-4(14a^2+41a+15)
=42a^3+123a^2+45a-56a^3-164a^2-60a
=-14a^3-41a^2-15a answer
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