Math, asked by amrutha39, 1 year ago

7a^5-567a (factorise)

Answers

Answered by TooFree
27

7a⁵ - 567a

Take out common factor 7a:

= 7a (a⁴ - 81)

Write each term in the bracket as a perfect square:

= 7a (( a²)² - (9)²)

Apply a² - b² = (a + b)(a - b):

= 7a ( a² + 9)(a² - 9)

Write the terms in the second bracket as a perfect square:

= 7a ( a² + 9)(a² - 3²)

Apply a² - b² = (a + b)(a - b):

= 7a ( a² + 9)(a - 3)(a + 3)


Answer: 7a ( a² + 9)(a - 3)(a + 3)



Answered by sarwerhussain1786
4

Answer:

7a ( a^2 + 9 ) ( a - 3 ) ( a + 3 )

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