Question

(7a+b–c+d)²+(d-b-5a+c)²+2(7a+d+b-c)(c+d-b-5a) express as a perfect square
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Answer 1

Answer:

{ (7a+d+b-c) + (c+d-b-5a)}^2

Step-by-step explanation:

Given,

(7a+b–c+d)²+(d-b-5a+c)²+2(7a+d+b-c)(c+d-b-5a)

We know that,

(a + b)^2 = a^2 + b^2 + 2ab

Hence by applying this identity in the expression we get,

=> (7a+b–c+d)²+(d-b-5a+c)²+2(7a+d+b-c)(c+d-b-5a) =

= { (7a+d+b-c) + (c+d-b-5a)}^2

Hence, the required answer =

{ (7a+d+b-c) + (c+d-b-5a)}^2