Math, asked by harikousthubh, 19 days ago

(7abc+b2)(7−bc)+c(2b3−9ab)​

Answers

Answered by mrudulakanade
1

Answer:

=(7abc+b³²) [7-bc) + c (26³-gab)

= 49abc+7b² - 7ab²c²-b³c +2b³c-9abc

→ 40abc + 76² - 7ab²c² + b³ c-)b(40ac +7b-7abc² + b²c ) ⁰40ac +7b-7abc² + b²c

Answered by stubalakrishnand8201
0

Answer:

=(7abc+b³²) [7-bc) + c (26³-gab)

= 49abc+7b² - 7ab²c²-b³c +2b³c-9abc

→ 40abc + 76² - 7ab²c² + b³ c-)b(40ac +7b-7abc² + b²c ) ⁰40ac +7b-7abc² + b²c

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