7g iron heated with excess sulphur.what amount of iron sulphide will be produced?
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11 gram, see on
Explanation:
1 st of all from the question S is Excess reagent
So calculate value wrt LR
Here Fe is LR => n(no. of mole of Fe) = no. of mole of FeS
=> 7/ 56 = x/ 88. Where x is unknown mass of Fes
So, x =11 gram
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