Question

7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 gas at 17degree c and the same pressure what is the molar mass of a gas

Answer 1

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Answer 2

Answer:

82.66`41.3320. 6710.332For hydrogen we known that `PV=(w) /(M)RT=(0.184)/(2)xxRxx290` For unknown gas ...

82.66`41.3320. 6710.332For hydrogen we known that `PV=(w) /(M)RT=(0.184)/(2)xxRxx290` For unknown gas ...3.7g of gas at 25oC occupies the same volume as 0.184g of .

82.66`41.3320. 6710.332For hydrogen we known that `PV=(w) /(M)RT=(0.184)/(2)xxRxx290` For unknown gas ...3.7g of gas at 25oC occupies the same volume as 0.184g of .What is the molecular mass of the gas? ... the same volume as 0.184g of Hydrogen at 17o C an

82.66`41.3320. 6710.332For hydrogen we known that `PV=(w) /(M)RT=(0.184)/(2)xxRxx290` For unknown gas ...3.7g of gas at 25oC occupies the same volume as 0.184g of .What is the molecular mass of the gas? ... the same volume as 0.184g of Hydrogen at 17o C an7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 ...

82.66`41.3320. 6710.332For hydrogen we known that `PV=(w) /(M)RT=(0.184)/(2)xxRxx290` For unknown gas ...3.7g of gas at 25oC occupies the same volume as 0.184g of .What is the molecular mass of the gas? ... the same volume as 0.184g of Hydrogen at 17o C an7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 ...30-Dec-2018 · 1 answer

82.66`41.3320. 6710.332For hydrogen we known that `PV=(w) /(M)RT=(0.184)/(2)xxRxx290` For unknown gas ...3.7g of gas at 25oC occupies the same volume as 0.184g of .What is the molecular mass of the gas? ... the same volume as 0.184g of Hydrogen at 17o C an7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 ...30-Dec-2018 · 1 answer7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 gas at 17degree c and the same pressure what is the ...

82.66`41.3320. 6710.332For hydrogen we known that `PV=(w) /(M)RT=(0.184)/(2)xxRxx290` For unknown gas ...3.7g of gas at 25oC occupies the same volume as 0.184g of .What is the molecular mass of the gas? ... the same volume as 0.184g of Hydrogen at 17o C an7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 ...30-Dec-2018 · 1 answer7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 gas at 17degree c and the same pressure what is the ...Q

82.66`41.3320. 6710.332For hydrogen we known that `PV=(w) /(M)RT=(0.184)/(2)xxRxx290` For unknown gas ...3.7g of gas at 25oC occupies the same volume as 0.184g of .What is the molecular mass of the gas? ... the same volume as 0.184g of Hydrogen at 17o C an7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 ...30-Dec-2018 · 1 answer7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 gas at 17degree c and the same pressure what is the ...Q3.7 g of a gas at 25^∘ occupied the same volume as 0.184 g of hydrogen at 17^∘C and at the same pressure. What is the molecular mass of the gas?

82.66`41.3320. 6710.332For hydrogen we known that `PV=(w) /(M)RT=(0.184)/(2)xxRxx290` For unknown gas ...3.7g of gas at 25oC occupies the same volume as 0.184g of .What is the molecular mass of the gas? ... the same volume as 0.184g of Hydrogen at 17o C an7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 ...30-Dec-2018 · 1 answer7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 gas at 17degree c and the same pressure what is the ...Q3.7 g of a gas at 25^∘ occupied the same volume as 0.184 g of hydrogen at 17^∘C and at the same pressure. What is the molecular mass of the gas?For hydrogen, w = 0.184 g T = 17 + 273 = 290 K M = 2 We know that, PV = wMRT = 0.1842 × R × 290 ... (i) For unknown gas, w = 3.7 g T = 25 + 273 = 298 K M = ? PV = 3.7M × R × 298 ... (ii) Equating both the equations, we get 3.7M × R × 298 = 0.1842 × R × 290 or M = 3.7 × 298 × 20.184 × 290 = 41.3

82.66`41.3320. 6710.332For hydrogen we known that `PV=(w) /(M)RT=(0.184)/(2)xxRxx290` For unknown gas ...3.7g of gas at 25oC occupies the same volume as 0.184g of .What is the molecular mass of the gas? ... the same volume as 0.184g of Hydrogen at 17o C an7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 ...30-Dec-2018 · 1 answer7g of a gas at 25 degree c occupied the same volume as 0.184g of h2 gas at 17degree c and the same pressure what is the ...Q3.7 g of a gas at 25^∘ occupied the same volume as 0.184 g of hydrogen at 17^∘C and at the same pressure. What is the molecular mass of the gas?For hydrogen, w = 0.184 g T = 17 + 273 = 290 K M = 2 We know that, PV = wMRT = 0.1842 × R × 290 ... (i) For unknown gas, w = 3.7 g T = 25 + 273 = 298 K M = ? PV = 3.7M × R × 298 ... (ii) Equating both the equations, we get 3.7M × R × 298 = 0.1842 × R × 290 or M = 3.7 × 298 × 20.184 × 290 = 41.3If 3.7 g of a gas at 25^∘ C occupies the same volume as 0.184 g of hydrogen at 17^∘ C and at the same pressure, then what is the molecular weight ( x × 10 ) of the

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