Question

7gN2, 1gH2, 8gO2, 20gNo2 which has maximum number of molecules

Answer 1

Answer:-

1g of H₂ has the maximum number of molecules.

Explanation:-

For 7g N₂ :-

• Molar mass of Nitrogen (N) = 14g/mol

Thus molar mass of N₂:-

= 14×2

= 28g/mol

No of moles in 7g N₂ :-

= Given Mass/Molar mass

= 7/28

= 0.25 mole

No of molecules:-

= No of moles × Avogadro Number

= 0.25×6.022×10²²

= 1.5055×10²³ molecules

For 1 g H₂ :-

• Molar mass of Hydrogen (H) = 1g/mol

Thus, molar mass of H₂:-

= 1×2

= 2g/mol

No of moles in 1g of H₂ :-

= 1/2

= 0.5 mole

No of molecules:-

= 0.5×6.022×10²²

= 3.011×10²³ molecules

For 8g of O₂ :-

• Molar mass of O2 = 16g/mol

Thus, molar mass of O₂:-

= 16×2

= 32g/mol

No of moles in 8g of O₃:-

= 8/32

= 0.25 mole

No of molecules:-

= 0.25×6.022×10²³

= 1.5055×10²³ molecules

For 20g of NO₂ :-

Molar mass of NO₂ :-

= 14+16×2

= 46g/mol

No of moles in 20g of NO₂ :-

= 20/46

= 0.43 mole

No of molecules:-

= 0.43×6.022×10²³

= 2.6×10²³ molecules

___________________________

Thus, 1g of H₂ has the maximum number of molecules i.e. 3.011×10²³.