7gr
A pendulum bob is given velocity u = at
V 2
lowest point where r is length of the string then the
minimum velocity of bob in subsequent motion is
gr
V=
then value of P is.
P
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Answer:
Using conservation of energy in vertical motion of pendulum when it reaches horizontal position,
2
1
mv
h
2
+mgL=
2
1
mv
b
2
Velocity at the bottom is given by,v
b
=
5gL
v
h
=
3gL
------ (1)
Tension at the horizontal position is =T=
L
mv
h
2
----- (2)
=3mg ; (Substituting v
h
from eqn 1 in eqn2)
∴ Net force on the bob is =
(3mg)
2
+(mg)
2
=
10
mg
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