Question

7log 7 (x ​​2-4x+5) = (x-1) , then x ∈ ????

Answer 1

Step-by-step explanation:

7^log(x²-4x+5)base 7 =x-1

x²-4x+5=x-1

x²-5x+6=0

x²-2x-3x+6=0

x(x-2)-3(x-2)=0

(x-2)(x-3)=0

x=2, x=3

Answer 2

Answer:

x=15.2

Step-by-step explanation:

7log7(2x-4x+5)=x-1

7log(3+4)(-2x+5)=x-1

put the value of log 3 &4

7(0.477+0.602)(-2x+5)=x-1

7*1.079(5+1)=X+2x

7.6*6=3x

45.6=3x

x=15.2

hope it help.........