Math, asked by bissu0615, 11 months ago

7m+2n/7m-2n=5/3, find (m^2+n^:m^2-n^2)

Answers

Answered by sanketj
4

 \frac{7m + 2n}{7m - 2n}  =  \frac{5}{3}  \\ 21m + 6n = 35m - 10n \\ 6n + 10n = 35m - 21m \\ 16n = 14m \\ 8n = 7m \\ n =  \frac{7}{8}m \\  {n}^{2}   =  \frac{49}{64}  {m}^{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ... \: (i) \\  \\   \:  \:  \:  \:  \: \frac{ {m}^{2}  +  {n}^{2} }{ {m}^{2}  -  {n}^{2} }  \\  =  \frac{ {m}^{2} +  \frac{49}{64} {m}^{2}   }{ {m}^{2}  -  \frac{49}{64}  {m}^{2} }  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ... \: from (i) \\  \\multiplying \: numerator \: and \: denominator \: by \:\\ 64\\ \\  =  \frac{64 {m}^{2} +  49 {m}^{2} }{64 {m}^{2} - 49 {m}^{2}  }  =  \frac{113 {m}^{2} }{15 {m}^{2} }  \\  =  \frac{113}{15}

Hence,

( + ):( - ) = 113:15

Answered by asmitamaskey99
1

*CHECK HERE*

IT WILL BE HELPFUL

Answer:

1) 8:7

2) 113: 15

Step-by-step explanation:

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