Question

7p²-5p-2=0 can anyone solve this quadratic equation formula

Answer 1

Answer:

Value of P = -2/7

or, P = 1

$\frac{ - 2}{7} or 1$

Step-by-step explanation:

${7p}^{2} - 5p - 2 = 0$

$\implies \: {7p}^{2} - 7p + 2p - 2 = 0$

$\implies \: 7p( p-1) + 2(p - 1) = 0$

$\implies \: (7p + 2)(p - 1) = 0$

Either 7P + 2 = 0. or, P-1 = 0

P = - 2/7. or, 1.

Answer 2

Answer:

p=1, p= -2/7

Step-by-step explanation:

7p²-5p-2=0

a=7, b=-5, c=-2

b²-4ac = (-5)²-4×7×(-2)

= 25-4×(-14)

= 25+56

= 81

p = -b±√b²-4ac / 2a

p = -(-5)±√81 / 2×7

p = 5 ±9 / 14

p= 5+9 / 14 OR p = 5-9 / 14

p= 14/14 p= -4/14

p = 1 p= -2/7