Question

7p²q² (9r27) ÷ 63pq(r − 3) ​

Answer 1

$\frac{7 {p}^{2} {q}^{2} \times 9(r - 3) }{63pq(r - 3)} \\ = p ^{2 - 1} q ^{2 - 1} \times 9 \\ = 9pq$

Answer 2

$\frac{7 {p}^{2} {q}^{2} \times 9(r - 3) }{63pq(r - 3)} \\ = p ^{2 - 1} q ^{2 - 1} \times 9 \\ = 9pq$