[7Question # 8:
Assume the number of trucks passing an intersection has a Poisson distribution with a mean of 5 trucks per minute. What is the probability of 0 or 1 trucks in one minute?
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Given : number of trucks passing an intersection has a Poisson distribution with a mean of 5 trucks per minute
To Find : probability of 0 or 1 trucks in one minute
Solution:
Poisson distribution
P(x) = { λˣ e^(-λ) } / x!
λ = Mean = 5
probability of 0 or 1 trucks in one minute
= P(0) + P(1)
P(0) = 5⁰ e⁻⁵ / 0! = 0.00674
P(1) = 5¹ e⁻⁵ / 1! = 0.03369
probability of 0 or 1 trucks in one minute = 0.00674 + 0.03369
= 0.04043
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