7r - 2 = 5( r + 2) - 4 solve the equation
Answers
Answer:
How to solve your problem
7
−
2
=
5
(
+
2
)
−
4
7r-2=5(r+2)-4
7r−2=5(r+2)−4
Solve
1
Distribute
7
−
2
=
5
(
+
2
)
−
4
7r-2={\color{#c92786}{5(r+2)}}-4
7r−2=5(r+2)−4
7
−
2
=
5
+
1
0
−
4
7r-2={\color{#c92786}{5r+10}}-4
7r−2=5r+10−4
2
Subtract the numbers
7
−
2
=
5
+
1
0
−
4
7r-2=5r+{\color{#c92786}{10}}{\color{#c92786}{-4}}
7r−2=5r+10−4
7
−
2
=
5
+
6
7r-2=5r+{\color{#c92786}{6}}
7r−2=5r+6
3
Add
2
2
2
to both sides of the equation
7
−
2
=
5
+
6
7r-2=5r+6
7r−2=5r+6
7
−
2
+
2
=
5
+
6
+
2
7r-2+{\color{#c92786}{2}}=5r+6+{\color{#c92786}{2}}
7r−2+2=5r+6+2
4
Simplify
Add the numbers
Add the numbers
7
=
5
+
8
7r=5r+8
7r=5r+8
5
Subtract
5
5r
5r
from both sides of the equation
7
=
5
+
8
7r=5r+8
7r=5r+8
7
−
5
=
5
+
8
−
5
7r{\color{#c92786}{-5r}}=5r+8{\color{#c92786}{-5r}}
7r−5r=5r+8−5r
6
Simplify
Combine like terms
Combine like terms
2
=
8
2r=8
2r=8
7
Divide both sides of the equation by the same term
2
=
8
2r=8
2r=8
2
2
=
8
2
\frac{2r}{{\color{#c92786}{2}}}=\frac{8}{{\color{#c92786}{2}}}
22r=28
8
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
4
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