Question

7sin^2+3cos^2=4 then the value of cot​

Answer 1

Hey there,

7sin²x + 3cos² = 4

4sin²x + (3sin²x + 3cos²x) = 4

4sin²x + 3(sin²x + cos²x) = 4

4sin²x + 3 = 4

4sin²x = 1

sin²x = 1/4

sin x = 1/2 P/H

Therefore, B² = H²-P²

4 - 1

B =

$\sqrt{3}$

Now, cot x = B/P

$\frac{ \sqrt{3} }{1}$

Hope it help

Answer 2

Answer:hey ur answer is √3

Step-by-step explanation:7sin^2 + 3cos^2 = 4

This can be written as

4sin^2 + 3sin^2 + 3cos^2 = 4

4sin^2 + 3(sin^2 + cos^2) = 4.....(1)

Sin^2 + cos^2 = 1 ( according to identity)

In equation (1)

4sin^2 + 3 = 4

4sin^2 = 1

Sin^2 =1/4

Sin = 1/2

Sin 30 = 1/2

Cot 30 = √3