7sin^2+3cos^2=4 then the value of cot
Answers
Answered by
3
Hey there,
7sin²x + 3cos² = 4
4sin²x + (3sin²x + 3cos²x) = 4
4sin²x + 3(sin²x + cos²x) = 4
4sin²x + 3 = 4
4sin²x = 1
sin²x = 1/4
sin x = 1/2 P/H
Therefore, B² = H²-P²
4 - 1
B =
Now, cot x = B/P
Hope it help
Answered by
0
Answer:hey ur answer is √3
Step-by-step explanation:7sin^2 + 3cos^2 = 4
This can be written as
4sin^2 + 3sin^2 + 3cos^2 = 4
4sin^2 + 3(sin^2 + cos^2) = 4.....(1)
Sin^2 + cos^2 = 1 ( according to identity)
In equation (1)
4sin^2 + 3 = 4
4sin^2 = 1
Sin^2 =1/4
Sin = 1/2
Sin 30 = 1/2
Cot 30 = √3
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