Question

7sin^2A+3cis^2A=4, show that tanA=1/√3.​

Answer 1

prove that your questions

Answer 2

GIVEN:-

$\large\sf{7 { \sin }^{2} a + 3 { \cos}^{2} a = 4}$

$\large\sf\green{Dividing\:both\:sides\:by\:{cos}^{2}A}$

$\large\sf\red{We\:get,}$

$\implies$$\large\sf{7{tan}^{2}A+3=4{sec}^{2}A}$

$\implies$$\large\sf{7{tan}^{2}A+3=4(1+{tan}^{2}A)}$

$\implies$$\large\sf{7{tan}^{2}A+3=4+4{tan}^{2}A}$

$\implies$$\large\sf{3{tan}^{2}A=1}$

$\implies$$\large\sf{{tan}^{2}A=\frac{1}{3}}$

$\implies$$\large\sf{tan\:A=\frac{1}{√3}}$