Question

7sin A - 24 COSA=0 then find then find the value of

Sec A​

Answer 1

the answer is secθ=25/7

i hope this helpful for you

Answer 2

Answer:

• secA = 25/7

Step-by-step explanation:

Given:

• 7sinA - 24cosA = 0

To find:

• The value of secA

Solution:

⇒ 7sinA-24cosA = 0

⇒ 7sinA = 24cosA

On dividing cosA in both LHS and RHS,

⇒ 7sinA/cosA = 24cosA/cosA

As we know that, sinA/cosA = tanA,

⇒ 7tanA = 24

⇒ tanA = 24/7

tanA = Perpendicular/Adjacent Side = 24/7

Let Perpendicular side of the triangle be 24k

Let Adjacent side of the triangle be 7k

According to Pythagoras Theorm, we know that:

⇒ (Hypotenuse)² = (Perpendicular)²+(Adjacent Side)²

⇒ (Hypotenuse)² = (24k)²+(7k)²

⇒ (Hypotenuse)² = 576k²+49k²

⇒ (Hypotenuse)² = 625k²

⇒ Hypotenuse = √625k²

⇒ Hypotenuse = 25k

Hence, we found all the sides of triangles. Now, we know that:

⇒ secA = Hypotenuse/Adjacent Side

⇒ secA = 25k/7k

⇒ secA = 25/7

Hence, secA = 25/7

Know more:

→ sinA = Perpendicular/Hypotenuse

→ cosA = Adjacent Side/Hypotenuse

→ tanA = sinA/cosA = Perpendicular/Adjacent Side

→ cosecA = 1/sinA = Hypotenuse/Perpendicular

→ secA = 1/cosA = Hypotenuse/Adjacent Side

→ cotA = 1/tanA = cosA/sinA = Adjacent Side/Perpendicular