7sin square theta+3 cos^theta=4 find sec theta +cosec theta
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Given
→ 7 sin²∅ + 3 cos²∅ = 4
Solution
→ 7 sin²∅ + 3 cos²∅ = 4
→ 4 sin²∅ + 3 sin²∅ + 3 cos²∅ = 4
→ 4 sin²∅ + 3(sin²∅ + cos²∅) = 4
→ 4 sin²∅ + 3 = 4
→ sin²∅ = ¼
→ sin∅ = ½
Hence value of ∅ is 30.
→ cosec∅ + sec∅
→ cosec 30° + sec 30°
→ 2 + 2/√3
→ 2 + 2√3/3
→ (6 + 2√3)/3
Hence required answer is (6 + 2√3)/3.
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