Math, asked by tiyasa2004, 8 months ago


7sin0+3cos0=4 find the value of 0 in circular system​

Answers

Answered by Anonymous
1

Answer:

This question is incorret but this question is correct

7sin^2X+3cosX=4

4sin^2X+3sin^2X+3cos^2X=4

4sin^2X+3 (sin^2X+cos^2X)=4

4sin^2X+3 (1)=4 (sin^2X+cos^2X)=1

4sin^2X+3=4

4sin^2=4-3

4sin^2X=1

sin^2X=1/4

sinX=1/2

so,

X=30

the value of X is 30

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