7sin²theta +3cos²theta=4 then prove sec theta+cosec theta=2+2/√3
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given 7sin^2 theta + cos ^2 theta = 4
putting cos^2 thata = 1 - sin^2 theta
now,
7sin^2 theta + 3(1 - sin^2 theta) = 4
solving it we get
sin theta = 1/2
and cosec theta = 2
similarly sec theta = 2/root3
which means que is solved
putting cos^2 thata = 1 - sin^2 theta
now,
7sin^2 theta + 3(1 - sin^2 theta) = 4
solving it we get
sin theta = 1/2
and cosec theta = 2
similarly sec theta = 2/root3
which means que is solved
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