7sin²x + 3cos²x = 4 , then find the value tanx ?
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Shaik96:
Consider the negative values also for complete description of answer
Answered by
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4sin²x + 3sin²x + 3cos²x = 4
4sin²x = 4−3=1
sin²x= 1/4
sinx = ±1/√2
So tanx = ± 1
This is the solution to this question....
I hope this helps you...
4sin²x = 4−3=1
sin²x= 1/4
sinx = ±1/√2
So tanx = ± 1
This is the solution to this question....
I hope this helps you...
It should should be ± ½ instead of ±1/√2
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