7sinA+24cosA=25 find the value of tanA. plz help
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since
7sinA+24cosA=25,
then
7/25 . sinA + 24/25 . cosA=1,
cosB . sinA + sinB . cosA=1, (where cosB=7/25 and sinB=24/25),
then
sin(A+B)=1,
sin(A+B)=sin90°,
A+B=90°,
A=90°-B,
therefore
tanA=tan(90°-B),
=cotB,
=7/24
7sinA+24cosA=25,
then
7/25 . sinA + 24/25 . cosA=1,
cosB . sinA + sinB . cosA=1, (where cosB=7/25 and sinB=24/25),
then
sin(A+B)=1,
sin(A+B)=sin90°,
A+B=90°,
A=90°-B,
therefore
tanA=tan(90°-B),
=cotB,
=7/24
ramesh1997rk31:
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