7th and 19th terms of an A.P. are respectively 148 and 100. Which term of A.P. will be zero
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Let a and d be the first term and the common difference of the given AP respectively. Then,
a19=52⇒a+18d=52 ...(1)
a38=148⇒a+37d=148 ...(2)
On subtracting (1) from (2), we get
19d=96⇒d=1996
Putting d=1996 in (1), we get
a=52−18×1996=19−740
Now, S56=256[2a+(56−1)d]
∴S56=28[193800]=5600
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