7th one please solve....
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equivalent resistance of n resistances connected in series
R = nr
equivalent resistance of n resistances connected in parallel
R' = n/ r
so
ratio = R/R'= nr/n/r
= r^2
R = nr
equivalent resistance of n resistances connected in parallel
R' = n/ r
so
ratio = R/R'= nr/n/r
= r^2
ppakhrani2gmailcom:
n gets cancelled
Answered by
1
Series combination:
Total Resistance
Rp = R₁ + R₂ + R₃ +.....n
= n Rₐ as all resistors are equivalent.
Parallel combination:
Total Resistance
1/Rq = 1/R₁ + 1/R₂ + 1/R₃ ..... 1/n
Rq = Rₐ/n as all resistors are equivalent.
Then ratio = Rp/Rq = n Rₐ/Rₐ/n
= n²
:) Hope this Helps !!!
Total Resistance
Rp = R₁ + R₂ + R₃ +.....n
= n Rₐ as all resistors are equivalent.
Parallel combination:
Total Resistance
1/Rq = 1/R₁ + 1/R₂ + 1/R₃ ..... 1/n
Rq = Rₐ/n as all resistors are equivalent.
Then ratio = Rp/Rq = n Rₐ/Rₐ/n
= n²
:) Hope this Helps !!!
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