Question

7th term of a h.p is 3/2 and its 10th term of 12/17 find the difference

Answer 1

So 7th term⇒ a+6d=3/2--------------eq 1
10th term ⇒a + 9d=12/17----------eq2
Subtracting eq1 from eq2, we get 3d=-27/34
d=-9/34

I hope that's correct

Answer 2

a+6d is 3/2
2a+12d is 3. (1)
a+9d is 12/17
17a+323d is 12. (2)
(1) multiply with 17
34a+204d is 51
(2) multiply with 2
34a+646d is 24
after elimination method the answer will be
-442d is equal to 27
d is equal to -27/442