7th term of a HP is 3/2 and its 10th term of 12/17 find the first term an common difference
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Answered by
6
a7=a+6d=3/2
a10=a+9d=12/17
using elimination method,
a will get cancel.
therefore-3d=3/2-12/17=51-24/34=27/34
d=-9/34
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a10=a+9d=12/17
using elimination method,
a will get cancel.
therefore-3d=3/2-12/17=51-24/34=27/34
d=-9/34
please mark my answer as brainliest
i hope this answer will help you
please feel free to ask doubts to me
Answered by
4
t7=2/3
t10=17/12
a+6d=2/3
a+9d=17/12
-3d=-3/4
d=1/4
a+6d=2/3
a+6(1/4)=2/3
a+6/4=2/3
a=2/3-4/6
a=1/6
t10=17/12
a+6d=2/3
a+9d=17/12
-3d=-3/4
d=1/4
a+6d=2/3
a+6(1/4)=2/3
a+6/4=2/3
a=2/3-4/6
a=1/6
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