Question

7th term of an AP is
terms
40. The sum of its first

13th
term is 520
as 530
b) 510
(a) 500​

Answer 1

Answer:

510 is the answer I now it it will be write I know you are in 10 std

Answer 2

Answer:

So the 7th term of the A.P. is 40=> a+6d =40. Sum of first 13 terms = 13/2(a +(a+12d))= 13/2(2a+12d) =13/2(2)(a+6d) =13(a+6d) =13(40)=520 .