7th term of an arthemetic sequence is 34 ond it's 15th
derm is 66. Find the common difference
Answers
Answered by
3
Answer:
d=4
Step-by-step explanation:
a7=34
a15=66
a7=a+6d. 1
a15= a+14d. 2
subtract 1from 2
a+14d=66
a+6d=34
d=32÷8
d=4
Answered by
0
common difference is 4
Step-by-step explanation:
a7=34
a15=66
therefore,
a7=a+6d
a=34-6d ...(1)
therefore,
a15=a+14d
a=66-14d ...(2)
therefore,
from (1) & (2),
34-6d=66-14d
therefore,
8d=32
therefore,
d=4
therefore,
The common difference is 4.
I hope it helps!!
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